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x(x-5)+3(x+2)=3
We move all terms to the left:
x(x-5)+3(x+2)-(3)=0
We multiply parentheses
x^2-5x+3x+6-3=0
We add all the numbers together, and all the variables
x^2-2x+3=0
a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation
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