x(x-5)=(x-3)(x+3)

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Solution for x(x-5)=(x-3)(x+3) equation: 



x(x-5)=(x-3)(x+3)

We move all terms to the left:

x(x-5)-((x-3)(x+3))=0

We use the square of the difference formula

x^2+x(x-5)+9=0

We multiply parentheses

x^2+x^2-5x+9=0

We add all the numbers together, and all the variables

2x^2-5x+9=0

a = 2; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·2·9
Δ = -47
Delta is less than zero, so there is no solution for the equation

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