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x(x-5)=369.-4
We move all terms to the left:
x(x-5)-(369.-4)=0
We add all the numbers together, and all the variables
x(x-5)-365=0
We multiply parentheses
x^2-5x-365=0
a = 1; b = -5; c = -365;
Δ = b2-4ac
Δ = -52-4·1·(-365)
Δ = 1485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1485}=\sqrt{9*165}=\sqrt{9}*\sqrt{165}=3\sqrt{165}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3\sqrt{165}}{2*1}=\frac{5-3\sqrt{165}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3\sqrt{165}}{2*1}=\frac{5+3\sqrt{165}}{2} $
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