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x(x-5)=59
We move all terms to the left:
x(x-5)-(59)=0
We multiply parentheses
x^2-5x-59=0
a = 1; b = -5; c = -59;
Δ = b2-4ac
Δ = -52-4·1·(-59)
Δ = 261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{261}=\sqrt{9*29}=\sqrt{9}*\sqrt{29}=3\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3\sqrt{29}}{2*1}=\frac{5-3\sqrt{29}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3\sqrt{29}}{2*1}=\frac{5+3\sqrt{29}}{2} $
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