x(x-6)=(x+2)(x-7)

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Solution for x(x-6)=(x+2)(x-7) equation: 



x(x-6)=(x+2)(x-7)

We move all terms to the left:

x(x-6)-((x+2)(x-7))=0

We multiply parentheses

x^2-6x-((x+2)(x-7))=0

We multiply parentheses ..

x^2-((+x^2-7x+2x-14))-6x=0



We calculate terms in parentheses: -((+x^2-7x+2x-14)), so:

(+x^2-7x+2x-14)

We get rid of parentheses

x^2-7x+2x-14

We add all the numbers together, and all the variables

x^2-5x-14

Back to the equation:

-(x^2-5x-14)



We add all the numbers together, and all the variables

x^2-6x-(x^2-5x-14)=0

We get rid of parentheses

x^2-x^2-6x+5x+14=0

We add all the numbers together, and all the variables

-1x+14=0

We move all terms containing x to the left, all other terms to the right

-x=-14

x=-14/-1

x=+14

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