x(x-7)-18+2x=-11x+82+6x

Solution for x(x-7)-18+2x=-11x+82+6x equation:

x(x-7)-18+2x=-11x+82+6x

We move all terms to the left:

x(x-7)-18+2x-(-11x+82+6x)=0

We add all the numbers together, and all the variables

x(x-7)+2x-(-5x+82)-18=0

We add all the numbers together, and all the variables

2x+x(x-7)-(-5x+82)-18=0

We multiply parentheses

x^2+2x-7x-(-5x+82)-18=0

We get rid of parentheses

x^2+2x-7x+5x-82-18=0

We add all the numbers together, and all the variables

x^2-100=0

a = 1; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·1·(-100)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*1}=\frac{20}{2}
=10
$