If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(x-7)=2x-6
We move all terms to the left:
x(x-7)-(2x-6)=0
We multiply parentheses
x^2-7x-(2x-6)=0
We get rid of parentheses
x^2-7x-2x+6=0
We add all the numbers together, and all the variables
x^2-9x+6=0
a = 1; b = -9; c = +6;
Δ = b2-4ac
Δ = -92-4·1·6
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*1}=\frac{9-\sqrt{57}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*1}=\frac{9+\sqrt{57}}{2} $
| −5(1−5k)−4(2k+5)=0 | | -5y/6=10 | | 2=1.5^t | | -3v/7=-21 | | −4x=−12 | | 6^4x-1=40 | | 4x^2-3=33 | | 5x^2+1=1126 | | 2x+3x-49=2x | | 50=3(a+16)-2(a-2) | | S=100/x | | 5+2x=102-5x-7 | | 75-(b-8)^2=39 | | x^2+2=443 | | | | 16^2m=4^3m+4 | | -6(n+5)=66 | | -16·2x+16·6-3·18x+3·3=-4·4x-4·17 | | 7Y(5x2)=31 | | t3-3t2+3t-1=0 | | 12-6x=1,5 | | 3+5×(2x-1)=-12 | | x2-10+25=0 | | -4(z-4)=20 | | 15/6=20/r | | t2+8t+16=0 | | 16(-2x+6)-3(18x-3)=4(-4x-17) | | (2s^2-1)^2=225 | | 16(-2x+6)-3(18x-3)=4(-4x-17)-16·2x+16·6-3·18x+3·3=-4·4x-4·17 | | X+(1/3x)=49 | | (2x+1)2+(x+1)=6x+47 | | -5(y+3)=20 |