x(x-8)=x(x+3)+99

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Solution for x(x-8)=x(x+3)+99 equation: 



x(x-8)=x(x+3)+99

We move all terms to the left:

x(x-8)-(x(x+3)+99)=0

We multiply parentheses

x^2-8x-(x(x+3)+99)=0



We calculate terms in parentheses: -(x(x+3)+99), so:

x(x+3)+99

We multiply parentheses

x^2+3x+99

Back to the equation:

-(x^2+3x+99)



We get rid of parentheses

x^2-x^2-8x-3x-99=0

We add all the numbers together, and all the variables

-11x-99=0

We move all terms containing x to the left, all other terms to the right

-11x=99

x=99/-11

x=-9

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