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x(x/2)+3=4x/5
We move all terms to the left:
x(x/2)+3-(4x/5)=0
We add all the numbers together, and all the variables
x(+x/2)-(+4x/5)+3=0
We multiply parentheses
x^2-(+4x/5)+3=0
We get rid of parentheses
x^2-4x/5+3=0
We multiply all the terms by the denominator
x^2*5-4x+3*5=0
We add all the numbers together, and all the variables
x^2*5-4x+15=0
Wy multiply elements
5x^2-4x+15=0
a = 5; b = -4; c = +15;
Δ = b2-4ac
Δ = -42-4·5·15
Δ = -284
Delta is less than zero, so there is no solution for the equation
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