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x(1-x)=0.16
We move all terms to the left:
x(1-x)-(0.16)=0
We add all the numbers together, and all the variables
x(-1x+1)-(0.16)=0
We add all the numbers together, and all the variables
x(-1x+1)-0.16=0
We multiply parentheses
-1x^2+x-0.16=0
a = -1; b = 1; c = -0.16;
Δ = b2-4ac
Δ = 12-4·(-1)·(-0.16)
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.36}}{2*-1}=\frac{-1-\sqrt{0.36}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.36}}{2*-1}=\frac{-1+\sqrt{0.36}}{-2} $
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