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x(16-x)=63
We move all terms to the left:
x(16-x)-(63)=0
We add all the numbers together, and all the variables
x(-1x+16)-63=0
We multiply parentheses
-1x^2+16x-63=0
a = -1; b = 16; c = -63;
Δ = b2-4ac
Δ = 162-4·(-1)·(-63)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2}{2*-1}=\frac{-14}{-2} =+7 $
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