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x(23/100)=90000
We move all terms to the left:
x(23/100)-(90000)=0
We add all the numbers together, and all the variables
x(+23/100)-90000=0
We multiply parentheses
23x^2-90000=0
a = 23; b = 0; c = -90000;
Δ = b2-4ac
Δ = 02-4·23·(-90000)
Δ = 8280000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8280000}=\sqrt{360000*23}=\sqrt{360000}*\sqrt{23}=600\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-600\sqrt{23}}{2*23}=\frac{0-600\sqrt{23}}{46} =-\frac{600\sqrt{23}}{46} =-\frac{300\sqrt{23}}{23} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+600\sqrt{23}}{2*23}=\frac{0+600\sqrt{23}}{46} =\frac{600\sqrt{23}}{46} =\frac{300\sqrt{23}}{23} $
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