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x(48+x)=3897
We move all terms to the left:
x(48+x)-(3897)=0
We add all the numbers together, and all the variables
x(x+48)-3897=0
We multiply parentheses
x^2+48x-3897=0
a = 1; b = 48; c = -3897;
Δ = b2-4ac
Δ = 482-4·1·(-3897)
Δ = 17892
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17892}=\sqrt{36*497}=\sqrt{36}*\sqrt{497}=6\sqrt{497}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-6\sqrt{497}}{2*1}=\frac{-48-6\sqrt{497}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+6\sqrt{497}}{2*1}=\frac{-48+6\sqrt{497}}{2} $
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