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x(7-6x)=(1-3x)(1+2x)
We move all terms to the left:
x(7-6x)-((1-3x)(1+2x))=0
We add all the numbers together, and all the variables
x(-6x+7)-((-3x+1)(2x+1))=0
We multiply parentheses
-6x^2+7x-((-3x+1)(2x+1))=0
We multiply parentheses ..
-6x^2-((-6x^2-3x+2x+1))+7x=0
We calculate terms in parentheses: -((-6x^2-3x+2x+1)), so:We get rid of parentheses
(-6x^2-3x+2x+1)
We get rid of parentheses
-6x^2-3x+2x+1
We add all the numbers together, and all the variables
-6x^2-1x+1
Back to the equation:
-(-6x^2-1x+1)
-6x^2+6x^2+1x+7x-1=0
We add all the numbers together, and all the variables
8x-1=0
We move all terms containing x to the left, all other terms to the right
8x=1
x=1/8
x=1/8
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