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x(x+6)=6075
We move all terms to the left:
x(x+6)-(6075)=0
We multiply parentheses
x^2+6x-6075=0
a = 1; b = 6; c = -6075;
Δ = b2-4ac
Δ = 62-4·1·(-6075)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-156}{2*1}=\frac{-162}{2} =-81 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+156}{2*1}=\frac{150}{2} =75 $
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