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x(x-0.3)=9
We move all terms to the left:
x(x-0.3)-(9)=0
We multiply parentheses
x^2-0.3x-9=0
a = 1; b = -0.3; c = -9;
Δ = b2-4ac
Δ = -0.32-4·1·(-9)
Δ = 36.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.3)-\sqrt{36.09}}{2*1}=\frac{0.3-\sqrt{36.09}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.3)+\sqrt{36.09}}{2*1}=\frac{0.3+\sqrt{36.09}}{2} $
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