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x(x-28)=150
We move all terms to the left:
x(x-28)-(150)=0
We multiply parentheses
x^2-28x-150=0
a = 1; b = -28; c = -150;
Δ = b2-4ac
Δ = -282-4·1·(-150)
Δ = 1384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1384}=\sqrt{4*346}=\sqrt{4}*\sqrt{346}=2\sqrt{346}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{346}}{2*1}=\frac{28-2\sqrt{346}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{346}}{2*1}=\frac{28+2\sqrt{346}}{2} $
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