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x(x-5)=x-9
We move all terms to the left:
x(x-5)-(x-9)=0
We multiply parentheses
x^2-5x-(x-9)=0
We get rid of parentheses
x^2-5x-x+9=0
We add all the numbers together, and all the variables
x^2-6x+9=0
a = 1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{6}{2}=3$
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