x*0.3x=3500

Solution for x*0.3x=3500 equation:

x*0.3x=3500

We move all terms to the left:

x*0.3x-(3500)=0

Wy multiply elements

0x^2-3500=0

We add all the numbers together, and all the variables

x^2-3500=0

a = 1; b = 0; c = -3500;
Δ = b2-4ac
Δ = 02-4·1·(-3500)
Δ = 14000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14000}=\sqrt{400*35}=\sqrt{400}*\sqrt{35}=20\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{35}}{2*1}=\frac{0-20\sqrt{35}}{2}
=-\frac{20\sqrt{35}}{2}
=-10\sqrt{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{35}}{2*1}=\frac{0+20\sqrt{35}}{2}
=\frac{20\sqrt{35}}{2}
=10\sqrt{35}
$