x*2(2-x)+(x-2)*3=-5(1-2x)+(2x+1)(1-2x)

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Solution for x*2(2-x)+(x-2)*3=-5(1-2x)+(2x+1)(1-2x) equation:



x*2(2-x)+(x-2)*3=-5(1-2x)+(2x+1)(1-2x)
We move all terms to the left:
x*2(2-x)+(x-2)*3-(-5(1-2x)+(2x+1)(1-2x))=0
We add all the numbers together, and all the variables
x*2(-1x+2)+(x-2)*3-(-5(-2x+1)+(2x+1)(-2x+1))=0
We multiply parentheses
x*2(-1x+2)+3x-(-5(-2x+1)+(2x+1)(-2x+1))-6=0
Wy multiply elements
2x^2(-+3x-(-5(-2x+1)+(2x+1)(-2x+1))-6=0
We multiply parentheses ..
2x^2(-+3x-(-5(-2x+1)+(-4x^2+2x-2x+1))-6=0
We use the square of the difference formula
2x^2(-3x-(-5(-2x+1)+(-4x^2+2x-2x+1))-6=0

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