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x*2x=392
We move all terms to the left:
x*2x-(392)=0
Wy multiply elements
2x^2-392=0
a = 2; b = 0; c = -392;
Δ = b2-4ac
Δ = 02-4·2·(-392)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*2}=\frac{-56}{4} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*2}=\frac{56}{4} =14 $
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