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x*2x=648
We move all terms to the left:
x*2x-(648)=0
Wy multiply elements
2x^2-648=0
a = 2; b = 0; c = -648;
Δ = b2-4ac
Δ = 02-4·2·(-648)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*2}=\frac{-72}{4} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*2}=\frac{72}{4} =18 $
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