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x*3x/2=216
We move all terms to the left:
x*3x/2-(216)=0
We multiply all the terms by the denominator
x*3x-216*2=0
We add all the numbers together, and all the variables
x*3x-432=0
Wy multiply elements
3x^2-432=0
a = 3; b = 0; c = -432;
Δ = b2-4ac
Δ = 02-4·3·(-432)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*3}=\frac{-72}{6} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*3}=\frac{72}{6} =12 $
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