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x*4x=900
We move all terms to the left:
x*4x-(900)=0
Wy multiply elements
4x^2-900=0
a = 4; b = 0; c = -900;
Δ = b2-4ac
Δ = 02-4·4·(-900)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*4}=\frac{-120}{8} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*4}=\frac{120}{8} =15 $
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