x+((20-x)/2)+((20-x)/2)=20

Solution for x+((20-x)/2)+((20-x)/2)=20 equation:

x+((20-x)/2)+((20-x)/2)=20

We move all terms to the left:

x+((20-x)/2)+((20-x)/2)-(20)=0

We add all the numbers together, and all the variables

x+((-1x+20)/2)+((-1x+20)/2)-20=0

We multiply all the terms by the denominator


x*2)+((-1x+20)+((-1x+20)-20*2)=0


We calculate terms in parentheses: +((-1x+20)-20*2), so:

(-1x+20)-20*2

We add all the numbers together, and all the variables

(-1x+20)-40

We get rid of parentheses

-1x+20-40

We add all the numbers together, and all the variables

-1x-20

Back to the equation:

+(-1x-20)


Wy multiply elements

2x^2+(-1x-20)=0

We get rid of parentheses

2x^2-1x-20=0

a = 2; b = -1; c = -20;
Δ = b2-4ac
Δ = -12-4·2·(-20)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{161}}{2*2}=\frac{1-\sqrt{161}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{161}}{2*2}=\frac{1+\sqrt{161}}{4}
$