x+((2x-1)/2)+8=0

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Solution for x+((2x-1)/2)+8=0 equation: 



x+((2x-1)/2)+8=0

We multiply all the terms by the denominator


x*2)+((2x-1)+8*2)=0

We add all the numbers together, and all the variables

x*2)+((2x-1)=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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