x+(.2x)=128

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Solution for x+(.2x)=128 equation: 



x+(.2x)=128

We move all terms to the left:

x+(.2x)-(128)=0

We add all the numbers together, and all the variables

x+(+.2x)-128=0

We get rid of parentheses

x+.2x-128=0

We add all the numbers together, and all the variables

1.2x-128=0

We move all terms containing x to the left, all other terms to the right

1.2x=128

x=128/1.2

x=106+0.8/1.2

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