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x+(1/2)x=1400
We move all terms to the left:
x+(1/2)x-(1400)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+(+1/2)x-1400=0
We multiply parentheses
x^2+x-1400=0
a = 1; b = 1; c = -1400;
Δ = b2-4ac
Δ = 12-4·1·(-1400)
Δ = 5601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{5601}}{2*1}=\frac{-1-\sqrt{5601}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{5601}}{2*1}=\frac{-1+\sqrt{5601}}{2} $
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