x+(1/5)x=18

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Solution for x+(1/5)x=18 equation:



x+(1/5)x=18
We move all terms to the left:
x+(1/5)x-(18)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x+(+1/5)x-18=0
We multiply parentheses
x^2+x-18=0
a = 1; b = 1; c = -18;
Δ = b2-4ac
Δ = 12-4·1·(-18)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{73}}{2*1}=\frac{-1-\sqrt{73}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{73}}{2*1}=\frac{-1+\sqrt{73}}{2} $

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