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x+(1/5x)=180
We move all terms to the left:
x+(1/5x)-(180)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+(+1/5x)-180=0
We get rid of parentheses
x+1/5x-180=0
We multiply all the terms by the denominator
x*5x-180*5x+1=0
Wy multiply elements
5x^2-900x+1=0
a = 5; b = -900; c = +1;
Δ = b2-4ac
Δ = -9002-4·5·1
Δ = 809980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{809980}=\sqrt{4*202495}=\sqrt{4}*\sqrt{202495}=2\sqrt{202495}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-900)-2\sqrt{202495}}{2*5}=\frac{900-2\sqrt{202495}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-900)+2\sqrt{202495}}{2*5}=\frac{900+2\sqrt{202495}}{10} $
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