x+(1/5x)=30

Solution for x+(1/5x)=30 equation:

x+(1/5x)=30

We move all terms to the left:

x+(1/5x)-(30)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+1/5x)-30=0

We get rid of parentheses

x+1/5x-30=0

We multiply all the terms by the denominator


x*5x-30*5x+1=0

Wy multiply elements

5x^2-150x+1=0

a = 5; b = -150; c = +1;
Δ = b2-4ac
Δ = -1502-4·5·1
Δ = 22480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22480}=\sqrt{16*1405}=\sqrt{16}*\sqrt{1405}=4\sqrt{1405}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-4\sqrt{1405}}{2*5}=\frac{150-4\sqrt{1405}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+4\sqrt{1405}}{2*5}=\frac{150+4\sqrt{1405}}{10}
$