x+(1/x)=(17/4)

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Solution for x+(1/x)=(17/4) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+1/x = 17/4 // - 17/4

x+1/x-(17/4) = 0

x+1/x-17/4 = 0

1*x^1+1*x^-1-17/4*x^0 = 0

(1*x^2-17/4*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-17/4*x^1+1*x^0) = 0

x^1

x^2+(-17/4)*x+1 = 0

x^2+(-17/4)*x+1 = 0

DELTA = (-17/4)^2-(1*1*4)

DELTA = 225/16

DELTA > 0

x = ((225/16)^(1/2)-(-17/4))/(1*2) or x = (-(-17/4)-(225/16)^(1/2))/(1*2)

x = 4 or x = 1/4

x in { 1/4, 4} 

x in { 1/4, 4 }

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