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x+(1/x+3)=5
We move all terms to the left:
x+(1/x+3)-(5)=0
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
x+1/x+3-5=0
We multiply all the terms by the denominator
x*x+3*x-5*x+1=0
We add all the numbers together, and all the variables
-2x+x*x+1=0
Wy multiply elements
x^2-2x+1=0
a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{2}{2}=1$
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