x+(10/100)x=5

Solution for x+(10/100)x=5 equation:

x+(10/100)x=5

We move all terms to the left:

x+(10/100)x-(5)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+10/100)x-5=0

We multiply parentheses

10x^2+x-5=0

a = 10; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·10·(-5)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{201}}{2*10}=\frac{-1-\sqrt{201}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{201}}{2*10}=\frac{-1+\sqrt{201}}{20}
$