x+(12/100*x)=1800

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Solution for x+(12/100*x)=1800 equation:



x+(12/100x)=1800
We move all terms to the left:
x+(12/100x)-(1800)=0
Domain of the equation: 100x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x+(+12/100x)-1800=0
We get rid of parentheses
x+12/100x-1800=0
We multiply all the terms by the denominator
x*100x-1800*100x+12=0
Wy multiply elements
100x^2-180000x+12=0
a = 100; b = -180000; c = +12;
Δ = b2-4ac
Δ = -1800002-4·100·12
Δ = 32399995200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{32399995200}=\sqrt{1600*20249997}=\sqrt{1600}*\sqrt{20249997}=40\sqrt{20249997}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180000)-40\sqrt{20249997}}{2*100}=\frac{180000-40\sqrt{20249997}}{200} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180000)+40\sqrt{20249997}}{2*100}=\frac{180000+40\sqrt{20249997}}{200} $

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