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x+(12/x+1)=-9
We move all terms to the left:
x+(12/x+1)-(-9)=0
Domain of the equation: x+1)!=0We add all the numbers together, and all the variables
x∈R
x+(12/x+1)+9=0
We get rid of parentheses
x+12/x+1+9=0
We multiply all the terms by the denominator
x*x+1*x+9*x+12=0
We add all the numbers together, and all the variables
10x+x*x+12=0
Wy multiply elements
x^2+10x+12=0
a = 1; b = 10; c = +12;
Δ = b2-4ac
Δ = 102-4·1·12
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{13}}{2*1}=\frac{-10-2\sqrt{13}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{13}}{2*1}=\frac{-10+2\sqrt{13}}{2} $
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