x+(2/3)x+(4/3)x=180

Solution for x+(2/3)x+(4/3)x=180 equation:

x+(2/3)x+(4/3)x=180

We move all terms to the left:

x+(2/3)x+(4/3)x-(180)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+2/3)x+(+4/3)x-180=0

We multiply parentheses

2x^2+4x^2+x-180=0

We add all the numbers together, and all the variables

6x^2+x-180=0

a = 6; b = 1; c = -180;
Δ = b2-4ac
Δ = 12-4·6·(-180)
Δ = 4321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4321}}{2*6}=\frac{-1-\sqrt{4321}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4321}}{2*6}=\frac{-1+\sqrt{4321}}{12}
$