x+(2/5x)=-35

Solution for x+(2/5x)=-35 equation:

x+(2/5x)=-35

We move all terms to the left:

x+(2/5x)-(-35)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+2/5x)-(-35)=0

We add all the numbers together, and all the variables

x+(+2/5x)+35=0

We get rid of parentheses

x+2/5x+35=0

We multiply all the terms by the denominator


x*5x+35*5x+2=0

Wy multiply elements

5x^2+175x+2=0

a = 5; b = 175; c = +2;
Δ = b2-4ac
Δ = 1752-4·5·2
Δ = 30585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(175)-\sqrt{30585}}{2*5}=\frac{-175-\sqrt{30585}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(175)+\sqrt{30585}}{2*5}=\frac{-175+\sqrt{30585}}{10}
$