x+(20/100)x=500

Solution for x+(20/100)x=500 equation:

x+(20/100)x=500

We move all terms to the left:

x+(20/100)x-(500)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+20/100)x-500=0

We multiply parentheses

20x^2+x-500=0

a = 20; b = 1; c = -500;
Δ = b2-4ac
Δ = 12-4·20·(-500)
Δ = 40001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{40001}}{2*20}=\frac{-1-\sqrt{40001}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{40001}}{2*20}=\frac{-1+\sqrt{40001}}{40}
$