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x+(2x)=(x+5)=29
We move all terms to the left:
x+(2x)-((x+5))=0
We add all the numbers together, and all the variables
3x-((x+5))=0
We calculate terms in parentheses: -((x+5)), so:We get rid of parentheses
(x+5)
We get rid of parentheses
x+5
Back to the equation:
-(x+5)
3x-x-5=0
We add all the numbers together, and all the variables
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2
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