x+(2x+1)+(x/3)=22

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Solution for x+(2x+1)+(x/3)=22 equation: 



x+(2x+1)+(x/3)=22

We move all terms to the left:

x+(2x+1)+(x/3)-(22)=0

We add all the numbers together, and all the variables

x+(2x+1)+(+x/3)-22=0

We get rid of parentheses

x+2x+x/3+1-22=0

We multiply all the terms by the denominator


x*3+2x*3+x+1*3-22*3=0

We add all the numbers together, and all the variables

x+x*3+2x*3-63=0

Wy multiply elements

x+3x+6x-63=0

We add all the numbers together, and all the variables

10x-63=0

We move all terms containing x to the left, all other terms to the right

10x=63

x=63/10

x=6+3/10

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