x+(2x+42)+(x-6)=180

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Solution for x+(2x+42)+(x-6)=180 equation: 



x+(2x+42)+(x-6)=180

We move all terms to the left:

x+(2x+42)+(x-6)-(180)=0

We get rid of parentheses

x+2x+x+42-6-180=0

We add all the numbers together, and all the variables

4x-144=0

We move all terms containing x to the left, all other terms to the right

4x=144

x=144/4

x=36

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