x+(2x-10)+(3x-50)=180

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Solution for x+(2x-10)+(3x-50)=180 equation: 



x+(2x-10)+(3x-50)=180

We move all terms to the left:

x+(2x-10)+(3x-50)-(180)=0

We get rid of parentheses

x+2x+3x-10-50-180=0

We add all the numbers together, and all the variables

6x-240=0

We move all terms containing x to the left, all other terms to the right

6x=240

x=240/6

x=40

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