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x+(2x-3)=12-(x-7)
We move all terms to the left:
x+(2x-3)-(12-(x-7))=0
We get rid of parentheses
x+2x-(12-(x-7))-3=0
We calculate terms in parentheses: -(12-(x-7)), so:We add all the numbers together, and all the variables
12-(x-7)
determiningTheFunctionDomain -(x-7)+12
We get rid of parentheses
-x+7+12
We add all the numbers together, and all the variables
-1x+19
Back to the equation:
-(-1x+19)
3x-(-1x+19)-3=0
We get rid of parentheses
3x+1x-19-3=0
We add all the numbers together, and all the variables
4x-22=0
We move all terms containing x to the left, all other terms to the right
4x=22
x=22/4
x=5+1/2
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