x+(2x-5)+(2(2x-5))/3=100

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Solution for x+(2x-5)+(2(2x-5))/3=100 equation: 



x+(2x-5)+(2(2x-5))/3=100

We move all terms to the left:

x+(2x-5)+(2(2x-5))/3-(100)=0

We get rid of parentheses

x+2x+(2(2x-5))/3-5-100=0

We multiply all the terms by the denominator


x*3+2x*3+(2(2x-5))-5*3-100*3=0



We calculate terms in parentheses: +(2(2x-5)), so:

2(2x-5)

We multiply parentheses

4x-10

Back to the equation:

+(4x-10)



We add all the numbers together, and all the variables

x*3+2x*3+(4x-10)-315=0

Wy multiply elements

3x+6x+(4x-10)-315=0

We get rid of parentheses

3x+6x+4x-10-315=0

We add all the numbers together, and all the variables

13x-325=0

We move all terms containing x to the left, all other terms to the right

13x=325

x=325/13

x=25

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