x+(2x-5)+(3x-19)=180

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Solution for x+(2x-5)+(3x-19)=180 equation:



x+(2x-5)+(3x-19)=180
We move all terms to the left:
x+(2x-5)+(3x-19)-(180)=0
We get rid of parentheses
x+2x+3x-5-19-180=0
We add all the numbers together, and all the variables
6x-204=0
We move all terms containing x to the left, all other terms to the right
6x=204
x=204/6
x=34

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