x+(2x-5)+(3x-19)=180

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Solution for x+(2x-5)+(3x-19)=180 equation: 



x+(2x-5)+(3x-19)=180

We move all terms to the left:

x+(2x-5)+(3x-19)-(180)=0

We get rid of parentheses

x+2x+3x-5-19-180=0

We add all the numbers together, and all the variables

6x-204=0

We move all terms containing x to the left, all other terms to the right

6x=204

x=204/6

x=34

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