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x+(2x-5)+(3x-19)=1806x-18=180
We move all terms to the left:
x+(2x-5)+(3x-19)-(1806x-18)=0
We get rid of parentheses
x+2x+3x-1806x-5-19+18=0
We add all the numbers together, and all the variables
-1800x-6=0
We move all terms containing x to the left, all other terms to the right
-1800x=6
x=6/-1800
x=-1/300
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