x+(2x-5)+(3x-19)=1806x-18=180

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Solution for x+(2x-5)+(3x-19)=1806x-18=180 equation: 



x+(2x-5)+(3x-19)=1806x-18=180

We move all terms to the left:

x+(2x-5)+(3x-19)-(1806x-18)=0

We get rid of parentheses

x+2x+3x-1806x-5-19+18=0

We add all the numbers together, and all the variables

-1800x-6=0

We move all terms containing x to the left, all other terms to the right

-1800x=6

x=6/-1800

x=-1/300

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