x+(2x-5)+(x-3)=78

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Solution for x+(2x-5)+(x-3)=78 equation: 



x+(2x-5)+(x-3)=78

We move all terms to the left:

x+(2x-5)+(x-3)-(78)=0

We get rid of parentheses

x+2x+x-5-3-78=0

We add all the numbers together, and all the variables

4x-86=0

We move all terms containing x to the left, all other terms to the right

4x=86

x=86/4

x=21+1/2

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