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x+(2x-5)+28=180
We move all terms to the left:
x+(2x-5)+28-(180)=0
We add all the numbers together, and all the variables
x+(2x-5)-152=0
We get rid of parentheses
x+2x-5-152=0
We add all the numbers together, and all the variables
3x-157=0
We move all terms containing x to the left, all other terms to the right
3x=157
x=157/3
x=52+1/3
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