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x+(2x-5)+62=180
We move all terms to the left:
x+(2x-5)+62-(180)=0
We add all the numbers together, and all the variables
x+(2x-5)-118=0
We get rid of parentheses
x+2x-5-118=0
We add all the numbers together, and all the variables
3x-123=0
We move all terms containing x to the left, all other terms to the right
3x=123
x=123/3
x=41
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